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2014-10-15T01:15:59Z jcowan: hey ho
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2014-10-15T03:00:50Z offby1: hup ho
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2014-10-15T03:09:02Z jusss: find a function , use which one fuction? i forget
2014-10-15T03:09:11Z jusss: apro someting
2014-10-15T03:11:22Z offby1: apropos?
2014-10-15T03:14:09Z jusss: offby1: yes,thanks
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2014-10-15T05:58:31Z jusss: hi all
2014-10-15T06:01:17Z jusss: which implement provide some socket procedure ?
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2014-10-15T15:52:54Z lrs: http://pastebin.com/Wiqqhfkg
2014-10-15T15:52:59Z lrs: Can anyone help me with this?
2014-10-15T15:53:09Z lrs: I am trying to make it so that this function
2014-10-15T15:53:23Z lrs: (define myset (makeset '(a a å å % %  4 4 a 5 5 (a b b (c b) 3) 5 a % 5 3 5 d a (e s) (s e s))))
2014-10-15T15:53:33Z lrs: > myset
2014-10-15T15:53:33Z lrs: {å 4 {a b b {c b} 3} % 3 5 d a {e s} {s e s}}
2014-10-15T15:54:04Z lrs: So that this function does the subsets
2014-10-15T15:54:11Z lrs: Too
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2014-10-15T15:54:33Z lrs: Right now it doesnt
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2014-10-15T16:18:45Z pjb`: lrs: It looks like it works perfectly well.  What else did you expect?
2014-10-15T16:18:56Z lrs: pjb`, It doesnt remove a bb
2014-10-15T16:19:02Z lrs:  {a b b {c b} 3}
2014-10-15T16:19:04Z lrs: ;_;
2014-10-15T16:19:10Z lrs: Its supposed to be  {a b  {c b} 3}
2014-10-15T16:19:13Z lrs: ;_;
2014-10-15T16:19:18Z pjb`: {a b b {c b} 3} occurs only once in your set.
2014-10-15T16:19:51Z pjb`: I see no reason why makeset should modify the elements.
2014-10-15T16:20:09Z lrs: Well, it should
2014-10-15T16:20:15Z pjb`: lrs: notice: this is a problem of specification: you didn't document it!
2014-10-15T16:20:39Z pjb`: YOU must write down in the docstrings, the specifications of the functions. Otherwise, there cannot be any bug.
2014-10-15T16:21:37Z lrs: ?
2014-10-15T16:22:07Z lrs: I will
2014-10-15T16:22:13Z lrs: If I get it to do wat I want it to
2014-10-15T16:23:49Z lrs: pjb`,
2014-10-15T16:23:50Z lrs: (define myset
2014-10-15T16:23:50Z lrs:      (make-set '(a (a b b (c b) 3) 5 5 (e s) (s e s))))
2014-10-15T16:23:53Z lrs: Is supposed to be
2014-10-15T16:23:57Z lrs: (a (a  b (c b) 3) 5 (e s))
2014-10-15T16:24:16Z lrs: Right now it check only the outer part
2014-10-15T16:25:13Z lrs: pjb`, And its probably something wrong
2014-10-15T16:25:14Z lrs: In member
2014-10-15T16:25:16Z lrs: I think
2014-10-15T16:25:17Z lrs: Fuck
2014-10-15T16:25:19Z lrs: I DONT KNOW
2014-10-15T16:25:21Z lrs: PLEASE HELP ME
2014-10-15T16:25:23Z lrs: ;_;
2014-10-15T16:27:07Z _tca: lrs: i'm not trying to be mean but have spent so much tie you could have finished the little schemer and the seasoned schemer, at which point this problem would be trivial for you to solve
2014-10-15T16:27:20Z _tca: but you have spent so much time*
2014-10-15T16:27:28Z lrs: _tca, I have read the whole chapter of relations
2014-10-15T16:27:33Z lrs: And it doesnt help me anymore
2014-10-15T16:27:40Z _tca: yes because you didn't read the book from the start
2014-10-15T16:27:44Z lrs: ...
2014-10-15T16:27:58Z _tca: you don't have the basics under your belt
2014-10-15T16:29:09Z lrs: What is the basics that I miss?
2014-10-15T16:29:34Z _tca: everything covered in the book
2014-10-15T16:30:18Z _tca: you need to practice for your braint o understand them at which point this becomes trivial, right now you are acting like you need some sort of black magic to solve this problem because you don't understand the basics
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2014-10-15T16:31:25Z lrs: _tca, Not really
2014-10-15T16:31:47Z _tca: then why not just write the procedure to do what you want
2014-10-15T16:32:06Z daviid joined #scheme
2014-10-15T16:32:17Z lrs: Thats because I thought it wrote the procedure that does what I want
2014-10-15T16:32:28Z _tca: i outlined it for you several days ago, all you have to do is recursively apply the duplicate removal, and run it a second time to get any new duplicates created by the changes
2014-10-15T16:32:29Z lrs: but apparently it skips the subdomains
2014-10-15T16:32:31Z lrs: For some reason
2014-10-15T16:32:40Z _tca: lrs: there is no such thing as subdomains
2014-10-15T16:32:42Z _tca: you have lists
2014-10-15T16:32:45Z lrs: Yes
2014-10-15T16:32:59Z lrs: Then why doesnt it just loops through it all
2014-10-15T16:33:09Z _tca: because that would make no sense
2014-10-15T16:33:17Z _tca: a list is an object
2014-10-15T16:33:22Z _tca: what if i want a set of lists
2014-10-15T16:33:33Z _tca: instead of a set of sets?
2014-10-15T16:34:45Z _tca: the normal way would be (make-set 1 1 2 (make-set 1 1 2) 3 3) ... not (make-set '(1 1 2 (1 1 2) 3 3))
2014-10-15T16:36:25Z _tca: what you want is not what would normally be thought of as a set, you would have to completely erase the idea of storing a list in the set, which in scheme makes no sense, and why all code relating to sets you will find in scheme material wont do what you want
2014-10-15T16:36:42Z _tca: you need to write your own remove-duplicates-recursively procedure
2014-10-15T16:37:00Z _tca: if you had actually written and understood the make-set code you have right now you would realize why it doesn't work
2014-10-15T16:37:14Z fridim_ quit (Ping timeout: 258 seconds)
2014-10-15T16:39:24Z _tca: if you dont understand how to write the code to do what you want, it means you need to learn and practice
2014-10-15T16:39:43Z _tca: starting the little schemer from the beginning and implementing all the exercises is a way to learn and practice
2014-10-15T16:43:47Z pjb`: lrs: Now, if you want to have unique atoms, why not do that over all the sublists?  I mean, why not (make-set '(a b (a b c) d)) --> (a b c d) or (a b (c) d)?
2014-10-15T16:44:13Z pjb` is now known as pjb
2014-10-15T16:46:23Z lrs: pjb, ?
2014-10-15T16:46:32Z pjb: I'm discussing your specifications.
2014-10-15T16:46:42Z Rodya_ quit (Quit: Ex-Chat)
2014-10-15T16:46:44Z lrs: '(a b (a b c) d)) = '(a b (a b c) d))
2014-10-15T16:47:32Z pjb: Here, I have a set containing two lists: ((a little lamb) (a dog ate a hot dog))
2014-10-15T16:47:59Z pjb: Why should (make-set '((a little lamb) (a dog ate a hot dog) (a little lamb))) --> ((a little lamb) (dog ate hot) ()) ?
2014-10-15T16:48:19Z pjb: These specifications are idiotic.
2014-10-15T16:48:46Z _tca: pls dont use language like that this isn't #lisp
2014-10-15T16:49:08Z lrs: _tca, Ok so I need to make this recursive
2014-10-15T16:49:08Z pjb: You could still impose them, but then name the function do-something-very-specific-and-strange, not make-set.
2014-10-15T16:49:12Z lrs: Right now it isnt recursive
2014-10-15T16:49:19Z lrs: Its I dont know, the opposite of recursive
2014-10-15T16:49:32Z pjb: _tca: what do you mean?
2014-10-15T16:49:34Z lrs: >(makeset '{a {a b b {c b} 3} 5 5 {e s} {s e s}})
2014-10-15T16:49:39Z lrs: > (makeset '{{a b b {c b} 3} 5 5 {e s} {s e s}})
2014-10-15T16:49:44Z lrs: THen it skips the subdomain
2014-10-15T16:49:49Z lrs: (makeset '{5 5 {e s} {s e s}})
2014-10-15T16:50:28Z oleo quit (Ping timeout: 244 seconds)
2014-10-15T16:50:36Z _tca: lrs: right now it doesn't distinguish between an atom: 1 and a list: (1 2 3)
2014-10-15T16:50:47Z lrs: RIGHT
2014-10-15T16:50:50Z lrs: THats my problem
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2014-10-15T16:50:56Z lrs: The atom shit
2014-10-15T16:51:11Z _tca: so you go to the part of the code where it does something with atoms
2014-10-15T16:51:27Z _tca: and put a case in front of it to do somethign different with lists
2014-10-15T16:51:34Z _tca: which will be to recur
2014-10-15T16:51:40Z lrs: member?
2014-10-15T16:52:10Z _tca: ((member? (car lst) (cdr lst))
2014-10-15T16:52:30Z _tca: it does the same thing no matter what (car lst) is
2014-10-15T16:52:38Z theseb quit (Read error: Connection reset by peer)
2014-10-15T16:52:44Z lrs: Do I need to create a cond?
2014-10-15T16:52:48Z _tca: yea
2014-10-15T16:54:04Z lrs: I need help
2014-10-15T16:54:07Z kongtomorrow quit
2014-10-15T16:54:20Z _tca: lrs: is there a reason it HAS to be like this though? did you consider what pjb said?
2014-10-15T16:54:31Z lrs: No it can be different
2014-10-15T16:54:47Z _tca: i.e. (makeset '(1 1 2 2 (3 3))) => '(1 2 3)
2014-10-15T16:54:50Z lrs: Or what do you mean? The subdomains should be unchanged
2014-10-15T16:54:55Z lrs: THats the point
2014-10-15T16:55:05Z lrs: Only remove the duplicates
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2014-10-15T16:57:54Z _tca: if (car lst) is a list, then makeset it THEN if that result of makeset is a member of the cdr, just return the cdr
2014-10-15T16:58:07Z _tca: otherwise just: if that result of makeset is a member of the cdr, just return the cdr
2014-10-15T16:58:14Z _tca: the otherwise is already there
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2014-10-15T17:00:41Z lrs: _tca: Do I have to define list? or is there a function that does htat
2014-10-15T17:01:07Z _tca: you could try it in a repl faster than asking me lol
2014-10-15T17:01:37Z _tca: it's a part of scheme
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2014-10-15T17:05:23Z lrs: _tca      ((list?  (car lst)) (member? (makeset (car lst)) (cdr lst))
2014-10-15T17:05:25Z lrs: :S
2014-10-15T17:08:12Z _tca: i would recommend getting rid of using (car lst) at all and instead let'ing it at the top of the procedure
2014-10-15T17:08:39Z lrs: Why is that?
2014-10-15T17:09:07Z _tca: because you will need the result of the recursive makeset both for the member test and to cons it on
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2014-10-15T17:09:23Z lrs: I havent used let
2014-10-15T17:09:27Z lrs: How would I write
2014-10-15T17:09:45Z _tca: (let ((variable-name value)) body)
2014-10-15T17:10:00Z lrs: Ugh
2014-10-15T17:10:11Z lrs: I dont understand let yet
2014-10-15T17:10:15Z lrs: How would i do it using this?
2014-10-15T17:11:06Z vanila: lrs: what are you trying to do?
2014-10-15T17:11:20Z lrs: Whats the variable name
2014-10-15T17:11:22Z lrs: ?
2014-10-15T17:11:38Z _tca: whatever you want to call it
2014-10-15T17:11:48Z pjdelport: lrs: I think it's been said many times before... but things like let are fundamentals. People are not being mean when they urge you to go read and study the fundamentals first, before tackling more advanced things... it's really important!
2014-10-15T17:12:27Z lrs: (let ((test (makeset lst)
2014-10-15T17:12:28Z lrs: ?
2014-10-15T17:12:40Z lrs: I dont even know how im gonna check its a list with that?
2014-10-15T17:13:49Z lrs: pjdelport, I will, I just need to complete this
2014-10-15T17:14:38Z vanila: lrs: What do you want to complete?
2014-10-15T17:14:40Z przl quit (Ping timeout: 255 seconds)
2014-10-15T17:15:03Z lrs: vanila, So that my function understands that it needs to remove duplicates of the subdomains in my set
2014-10-15T17:15:19Z lrs: _tca said I need to add an condition that checks if its a list
2014-10-15T17:15:34Z lrs: And if it is a list it has to do recursive call of car lst of that or something
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2014-10-15T17:15:47Z vanila: lrs, So you want to remove duplicates from a list
2014-10-15T17:16:05Z vanila: lrs, Or do you already have a way to do that?
2014-10-15T17:16:08Z pjdelport: (vanila: for context, http://pastebin.com/Wiqqhfkg )
2014-10-15T17:17:19Z lrs: vanila, I have managed to remove the outer layer of the domain
2014-10-15T17:17:24Z vanila: that's good
2014-10-15T17:17:31Z vanila: do you have a procedure that removes duplicates from a list?
2014-10-15T17:17:32Z lrs: But when it comes to the subdomains it doesnt understand that its an element
2014-10-15T17:17:43Z lrs: So it just skips them
2014-10-15T17:18:25Z lrs: vanila, Yes
2014-10-15T17:18:43Z vanila: cool!
2014-10-15T17:18:45Z vanila: Can I see it?
2014-10-15T17:18:52Z lrs: http://pastebin.com/Wiqqhfkg
2014-10-15T17:19:22Z vanila: That looks like really good!
2014-10-15T17:19:32Z lrs: But
2014-10-15T17:19:58Z lrs: (define myset (makeset '(a (a b b (c b) 3) 5 a 5 (e s) (s e s))))
2014-10-15T17:20:04Z vanila: http://lpaste.net/112630
2014-10-15T17:20:23Z vanila: here's how to edit it so that it makes sets out of the contained sets
2014-10-15T17:20:36Z pjb: There's little point to write a function that perform the two operations at once.  Functions should perform a single operation.  Then you can combine them.
2014-10-15T17:20:43Z lrs: vanila,
2014-10-15T17:21:07Z pjb: In this case, you would still get O(n) time complexity, even if the constant would be higher.
2014-10-15T17:21:15Z lrs: (define myset
2014-10-15T17:21:15Z lrs:      (make-set '(a (a b b (c b) 3) 5 5 (e s) (s e s))))
2014-10-15T17:21:22Z lrs: Should become
2014-10-15T17:21:22Z lrs: (a (a  b (c b) 3) 5 (e s))
2014-10-15T17:21:39Z vanila: lrs, Have you looked at what I posted? I think it will help you understand how to do this
2014-10-15T17:24:09Z lrs: vanila, contract violation - expected pair
2014-10-15T17:24:23Z lrs: its something with the member defition
2014-10-15T17:24:49Z vanila: lrs, Oh, I know what the issue is
2014-10-15T17:24:59Z vanila: I showed to add a case for      ((symbol? lst) lst)
2014-10-15T17:25:10Z vanila: but we also need one for ((number? lst) lst)
2014-10-15T17:25:42Z lrs: Damn! Worked
2014-10-15T17:26:02Z _tca: you can use atom?
2014-10-15T17:26:06Z _tca: to cover all the cases
2014-10-15T17:26:14Z vanila: lrs, Do you see what the change on ;;;;;;;; THIS LINE  did?
2014-10-15T17:27:10Z lrs: No
2014-10-15T17:28:34Z vanila: lrs, normally  (make-set '(a b b (c b) 3)) would look at: a, b, b, (c b), 3
2014-10-15T17:28:43Z vanila: lrs, when we change ;;;;;;;; THIS LINE  to do recursion too
2014-10-15T17:28:51Z vanila: lrs,  (make-set '(a b b (c b) 3)) would look at: a, b, b, (c b), c, b, 3
2014-10-15T17:29:04Z pjb: lrs: http://paste.lisp.org/+335H
2014-10-15T17:29:30Z _tca: you guys missed a part :p
2014-10-15T17:29:57Z pjb: lrs: sets are not ordered usually.
2014-10-15T17:29:57Z _tca: => .... (e s) (e s))
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2014-10-15T17:30:48Z pjb: notice the third parameter to remove-duplicates in recursive-make-set
2014-10-15T17:31:17Z lrs: Is it ok if I write commentaries about each thing and maybe you can correct me what is right and wrong?
2014-10-15T17:31:24Z pjb: Again, the specifications are very weak.
2014-10-15T17:31:31Z vanila: lrs, That's a great idea
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2014-10-15T17:39:08Z lrs: vanila, So
2014-10-15T17:39:19Z lrs: Im not sure I get that
2014-10-15T17:40:10Z lrs: http://pastebin.com/gef8ucyc
2014-10-15T17:40:43Z lrs: Thats my comments, but I would like a bit more description of  (else (cons (makeset(car lst)) ; else
2014-10-15T17:40:43Z lrs:                   (makeset (cdr lst))
2014-10-15T17:42:37Z vanila: lrs, here's how I think about it http://lpaste.net/112634
2014-10-15T17:43:29Z vanila: (which removes duplicates?) <- That's right - making something into a set removes the duplicates
2014-10-15T17:43:57Z lrs: the way I saw it
2014-10-15T17:44:13Z lrs: Was that it goes from (a b c d a)
2014-10-15T17:44:20Z lrs: And then finds a
2014-10-15T17:44:22Z lrs: car a
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2014-10-15T17:44:32Z lrs: And then checks if a is a member of b c d a
2014-10-15T17:44:37Z lrs: And it says, yes
2014-10-15T17:44:51Z vanila: yes, good :)
2014-10-15T17:44:53Z lrs: Then it chose to take the latter a
2014-10-15T17:45:43Z lrs: vanila, Im not really sure what you mean symbol called list though
2014-10-15T17:45:54Z lrs: And also maybe I need a description exactly what member? does
2014-10-15T17:46:05Z vanila: lrs, In that case: lst names a symbol
2014-10-15T17:46:13Z vanila: lst ;=> foo
2014-10-15T17:46:15Z vanila: rather than
2014-10-15T17:46:24Z vanila: lst being a list like (a b c)
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2014-10-15T17:48:09Z lrs: vanila, symbol and number checks the whole input then?
2014-10-15T17:48:19Z lrs: if i do makeset (1 2 3 a)
2014-10-15T17:48:36Z lrs: It checks if the whole (1 2 3 a) is a symbol? and if thats true it gives lst?
2014-10-15T17:48:48Z vanila: yes
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2014-10-15T17:50:03Z lrs: vanila, I dont get it. (1 2 3 a a) is a symbol. But, it doesnt do the duplication but still gives out lst
2014-10-15T17:50:12Z vanila: (1 2 3 a a) is not a symbol
2014-10-15T17:50:22Z vanila: (symbol? '(1 2 3 a a)) ;=> #f
2014-10-15T17:50:26Z vanila: it's a list
2014-10-15T17:50:31Z lrs: Ah
2014-10-15T17:50:47Z lrs: So number? and symbol?
2014-10-15T17:50:50Z lrs: Is only correct when
2014-10-15T17:51:01Z lrs: (makeset #) (makeset 1)
2014-10-15T17:51:02Z lrs: etc
2014-10-15T17:51:05Z vanila: number? holds for 0, 1, 2, 3, ...
2014-10-15T17:51:12Z vanila: symbol? for foo, bar, baz, ...
2014-10-15T17:51:47Z lrs: Ok then I get it
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2014-10-15T17:52:11Z lrs: Also, whats the difference (c b) c, b and (c b), 3
2014-10-15T17:52:18Z lrs: In the example you had a bit up
2014-10-15T17:52:28Z vanila: It processes inside (c b)
2014-10-15T17:52:35Z vanila: that's the extra recursion step
2014-10-15T17:52:52Z lrs: So when it comes to (c b)
2014-10-15T17:53:09Z lrs: It does symbol? number? null? member?
2014-10-15T17:53:16Z lrs: And then it comes to else, righ?
2014-10-15T17:53:21Z vanila: yes exactly
2014-10-15T17:53:25Z vanila: it does make-set on (c b)
2014-10-15T17:53:35Z vanila: which gives back (c b)
2014-10-15T17:53:38Z vanila: another example would be if you passed in (c c b b), since it processes inside that you would get (c b)
2014-10-15T17:54:06Z lrs: So it does the same thing that you do when you "start" the function, just that it is a loop
2014-10-15T17:54:28Z lrs: Or something like that
2014-10-15T17:54:59Z vanila: exactly right!
2014-10-15T17:55:06Z lrs: Cool!
2014-10-15T17:56:28Z theseb quit (Quit: Leaving)
2014-10-15T17:59:34Z lrs: vanila, http://pastebin.com/BYdZG34N Heres my attempt at describing member?, do you think it is right?
2014-10-15T18:00:44Z vanila: lrs, That's a really good explanation - well done :)
2014-10-15T18:00:50Z lrs: Nice!
2014-10-15T18:00:56Z lrs: Getting the hang of this now
2014-10-15T18:03:35Z lrs: Thanks alot for the help guys
2014-10-15T18:03:36Z lrs: Really
2014-10-15T18:04:06Z lrs: Gonna continue on with my function that checks if sets are identical now I think
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2014-10-15T18:13:40Z lrs: vanila, Well, there is one problem
2014-10-15T18:14:01Z vanila: what is it?
2014-10-15T18:14:10Z lrs: (a (a b b (c b) 3) 5 5 (e s) (s e s)))) produces  {{a b {c b} 3} 5 {e s} {e s}}
2014-10-15T18:14:12Z lrs: And not
2014-10-15T18:14:19Z lrs:  {{a b {c b} 3} 5 {e s}}
2014-10-15T18:14:27Z vanila: oh, well spotted!
2014-10-15T18:14:41Z vanila: so it compares (e s) with (s e s)
2014-10-15T18:14:49Z vanila: and they are equal as sets, but not as lists
2014-10-15T18:14:56Z lrs: Right
2014-10-15T18:16:25Z lrs: vanila, Do I need to do a member? check in makeset (car lst) or something?
2014-10-15T18:16:33Z lrs: Or do I need to define a new function?
2014-10-15T18:16:44Z vanila: I think there are a few ways to solve this,
2014-10-15T18:17:02Z kongtomorrow quit
2014-10-15T18:17:33Z vanila: do you know MAP?
2014-10-15T18:17:40Z lrs: Yes
2014-10-15T18:18:13Z vanila: maybe make-set could do MAP make-set, then remove duplicates on that
2014-10-15T18:18:55Z lrs: So I call it again basically
2014-10-15T18:18:57Z lrs: When im done
2014-10-15T18:19:04Z vanila: so (a (a b b (c b) 3) 5 5 (e s) (s e s)))) gets turned into (a {a b {c b} 3} 5 5 {e s} {e s})  before turned into {a {a b {c b} 3} 5 {e s} {e s}}
2014-10-15T18:19:16Z vanila: That would work too!
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2014-10-15T18:20:19Z lrs: How would I write that exactly
2014-10-15T18:20:28Z lrs: It would have to check that would b the case
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2014-10-15T18:22:06Z vanila: You could start by making a remove-duplicates function on its own, then write make-set from scratch: Testing if it's a symbol? or number? or if it's a list then map make-set over it and delete duplicates
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2014-10-15T18:26:03Z lrs: vanila, over what exactly
2014-10-15T18:26:08Z vanila: lst
2014-10-15T18:26:24Z lrs: Should it be a condition?
2014-10-15T18:26:31Z vanila: yes
2014-10-15T18:26:43Z lrs: So its identical to makeset
2014-10-15T18:26:44Z lrs: ?
2014-10-15T18:26:52Z lrs: Except that it has a extra condition?
2014-10-15T18:27:16Z vanila: im not sure, I'd say write it from scratch
2014-10-15T18:27:23Z vanila: start with blank canvas
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2014-10-15T18:35:19Z lrs: vanila, map doesnt work because it's on the form {a {a b {c b} 3} 5 {e s} {e s}}
2014-10-15T18:37:56Z lrs scratches head
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2014-10-15T18:48:01Z azathoth99: is there a cpan for scheme?
2014-10-15T18:48:23Z ijp: hi gavino
2014-10-15T18:48:36Z azathoth99: hey ijp
2014-10-15T18:48:41Z ijp: back to the classic nicks, I see
2014-10-15T18:48:47Z azathoth99 is now known as gavino_himself
2014-10-15T18:48:56Z gavino_himself: are u keeping track?
2014-10-15T18:49:12Z gavino_himself: who are you again?
2014-10-15T18:49:20Z ijp: just some internet jerkoff
2014-10-15T18:49:27Z gavino_himself: lol
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2014-10-15T18:52:48Z gavino_himself: Ian Price
2014-10-15T18:52:52Z amoe quit (Ping timeout: 246 seconds)
2014-10-15T18:53:11Z gavino_himself: england lost both world wars to Germany and USA saved them
2014-10-15T18:53:21Z gavino_himself: you know that right?
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2014-10-15T18:54:39Z zacts: unbelievable
2014-10-15T18:54:40Z ecraven: gavino_himself: how is that relevant to Scheme?
2014-10-15T18:54:52Z zacts ignores gavino
2014-10-15T18:54:55Z Riastradh: How is Gavino relevant to Scheme?
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2014-10-15T18:55:52Z mario-goulart: He (she? it?) is part of the troll history schemers feed. :-)
2014-10-15T18:55:58Z gavino_himself: how is demand side economics relevant to the huge deficits and falling productivity of europe?
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2014-10-15T18:56:17Z gnomon: What is the airspeed of a coconut laden swallow?
2014-10-15T18:56:19Z ijp: well, at least if gavino is talking crap about history rather than scheme, the newbies don't get confused and take him seriously
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2014-10-15T18:56:29Z ijp: I think that is a net win
2014-10-15T18:56:35Z gnomon: ijp++
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2014-10-15T18:56:38Z ecraven: gnomon: now *that* is more relevant!
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2014-10-15T18:58:01Z mario-goulart: gavino is quite amazing in some bizarre sense.  He has been trolling schemers longer than a lot of people actually use scheme.
2014-10-15T18:58:44Z ijp: yeah, it is quite weird
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2014-10-15T18:59:16Z gnomon: mario-goulart, there's another nitwit over in #awk who does the same, and for approximately as long.  It's odd how the trolls become fixtures.
2014-10-15T18:59:21Z aap__ is now known as aap_
2014-10-15T18:59:51Z mario-goulart: gnomon: isn't "it" gavino under another name?
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2014-10-15T19:00:00Z Riastradh: Not just Scheme either.
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2014-10-15T19:00:57Z gnomon: mario-goulart, is it?  The nitwit in #awk changes his/her/its/their nickname pretty regularly, but the tone and content is unmistakable.
2014-10-15T19:01:41Z mario-goulart: Some people complain gavino uses to troll some BSD-related channels too.
2014-10-15T19:01:48Z mario-goulart: #netbsd, for example.
2014-10-15T19:02:36Z gnomon: The #awk troll-in-residence has most recently gone by g0ph3r, y0tta9, Gst96, and invitado73.
2014-10-15T19:02:55Z gnomon: Let me cross-reference those hostnames with the ones gavino has used.
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2014-10-15T19:12:21Z lrs: vanila, Help!
2014-10-15T19:12:43Z vanila: what is ti?
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2014-10-15T19:15:54Z lrs: vanila, I assume map works like this : (map function list)
2014-10-15T19:15:58Z lrs: So I made a function square
2014-10-15T19:16:03Z lrs: (map square myset)
2014-10-15T19:16:14Z lrs:   given: a
2014-10-15T19:16:14Z lrs:   argument position: 1st
2014-10-15T19:16:14Z lrs:   other arguments...:
2014-10-15T19:16:14Z lrs:    a
2014-10-15T19:16:28Z lrs: I also tried doing a remove duplicates lst
2014-10-15T19:16:57Z vanila: you're right about map
2014-10-15T19:17:07Z vanila: and remove duplicates is useful to have for this
2014-10-15T19:17:21Z lrs: Right, but im supposed to write this by myself
2014-10-15T19:17:22Z vanila: (map square '(1 2 3 4)) ;=> (1 4 9 16)
2014-10-15T19:18:17Z lrs: vanila, Yup.
2014-10-15T19:18:53Z lrs: vanila, myset is  {a {a b {c b} 3} 5 {e s} {e s}}
2014-10-15T19:19:02Z lrs: I dont know if the } is different from ) ?
2014-10-15T19:20:37Z vanila: well I guess {} means set and () means list
2014-10-15T19:20:50Z lrs: Thats what I guessed to
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2014-10-15T19:25:02Z lrs: vanila, Do you think I need to replace them with ( to get this to work?
2014-10-15T19:25:42Z vanila: I don't think so:  You can process the lists to produce sets
2014-10-15T19:26:27Z lrs: vanila, So I can apply things to myset which is  {a {a b {c b} 3} 5 {e s} {e s}}
2014-10-15T19:26:45Z lrs: Or do I need to change the definition of myset in some way
2014-10-15T19:29:52Z lrs scratches head
2014-10-15T19:37:19Z lrs: Well, it has to have '
2014-10-15T19:37:23Z lrs: Before
2014-10-15T19:37:28Z lrs: Otherwise it dont get it
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2014-10-15T21:17:15Z offby1: rudybot: (set '(1 2 3 ))
2014-10-15T21:17:16Z rudybot: *offby1: your sandbox is ready
2014-10-15T21:17:16Z rudybot: *offby1: ; Value: (set '(1 2 3))
2014-10-15T21:17:31Z offby1: lrs: I don't think {} is standard reader syntax for anything
2014-10-15T21:17:51Z lrs: offby1, Then why do I got it ? :|
2014-10-15T21:17:54Z offby1: rudybot: (make '(a a (a b b (c b) 3) 5 5 (e s) (s e s)))
2014-10-15T21:17:54Z rudybot: *offby1: error: make: undefined; <NEWLINE>  cannot reference an identifier before its definition <NEWLINE>   in module: 'program
2014-10-15T21:17:59Z offby1: rudybot: (set '(a a (a b b (c b) 3) 5 5 (e s) (s e s)))
2014-10-15T21:17:59Z rudybot: *offby1: ; Value: (set '(a a (a b b (c b) 3) 5 5 (e s) (s e s)))
2014-10-15T21:18:10Z offby1: lrs: you may be using a scheme that has introduced a nonstandard extension
2014-10-15T21:18:17Z offby1: many do
2014-10-15T21:18:21Z lrs: I use racket
2014-10-15T21:18:29Z offby1: since the standard (at least, the older versions) doesn't provide much
2014-10-15T21:18:41Z offby1: lrs: curiously, rudybot is racket too; and he isn't displaying {}
2014-10-15T21:18:49Z offby1: lrs: which "language" are you using?
2014-10-15T21:18:54Z lrs: "Pretty Big"
2014-10-15T21:18:57Z offby1: ah.
2014-10-15T21:19:08Z offby1: I can never remember if rudybot "does" those student languages ...
2014-10-15T21:19:14Z offby1: rudybot: init "Pretty Big"
2014-10-15T21:19:14Z rudybot: *offby1: expecting: init [<lang>]
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2014-10-15T21:22:37Z lrs: offby1, So I dont have to replace
2014-10-15T21:22:42Z lrs: { with (
2014-10-15T21:22:43Z lrs: :S
2014-10-15T21:22:48Z offby1: dunno
2014-10-15T21:24:10Z lrs: offby1,
2014-10-15T21:24:14Z lrs: repl.it gives (
2014-10-15T21:24:16Z lrs: :S
2014-10-15T21:26:20Z lrs: offby1, I think its ok.
2014-10-15T21:26:44Z lrs:  (map makeset myset) works
2014-10-15T21:26:51Z lrs: But it doesnt do what I  want it to
2014-10-15T21:26:54Z lrs: ;_;
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2014-10-15T22:12:03Z lrs: I found the problem
2014-10-15T22:12:14Z lrs: Im supposed to change equal? to same-element
2014-10-15T22:12:22Z lrs: Im not really sure exactly how Im gonna change it
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